They call me a StackOverflow expert:

private bool isEven(int num) {
if (num == 0) return true;
if (num == 1) return false;
if (num ＜ 0) return isEven(-1 * num);
return isEven(num - 2);
}

Wow. Amateur hour over here. There's a much easier way to write this.

A case select:

select(number){
    case 1:
        return false;
    case 2:
        return true;
}

And so on.

Just do a while loop and subtract 2 if it's positive or plus 2 is it's negative until it reaches 1 or 0 and that's how you know, easy! /s

This is your brain on python:

def is_even (num):
     return num in [x*2 for x in range(sys.maxsize / 2)]

The number of comments posting a better solution is funny and somewhat concerning.

You have to make it easy on yourself and just use a switch with default true for evens, then gandle all the odd numbers in individual cases. There, cut your workload in half.

while (true){
    if (number == 0) return true;
    if (number == 1) return false;
    number -= 2
}

Because YandereDev is a legendary moron I can't even tell if this is a joke or not.

Oh man, in js we have a package for this magic.

Good job my young padawan, let me teach you about the modulo operator ...

OMG they can’t even!

number == 0 is not handled

string taco = variable.ToString()[variable.ToString().Length - 1];

If (taco == "0" || taco == "2" || taco == "4" || taco == "6" || taco == "8")

return true;

else

return false;

Im something of a coding master myself

Ok looks like this might be the source, and I suspect it is actually satirical. Not yanderedev, but yeah... wouldn't put it past him.

https://www.reddit.com/r/ProgrammerHumor/comments/i15h4d/iseven/

We're too swamped for that kind of thinking. Just keep typing or we'll never make our release window

int is_even(int n)
{
    int result = -1;
    char number[8]; //should be enough
    sprintf(number, "%d", n);

    // check the number
    // TODO: handle negative numbers
    for (char *p=number; *p; p++)
    {
        if (*p=='0' || *p=='2' || *p=='4' || *p=='6' || *p=='8')
            result = 1;
        else if (*p=='1' || *p=='3' || *p=='5' || *p=='7' || *p=='9')
            result = 0;
        else
           sprintf(stderr, "Your number is wrong!\n");
           exit(1); 
    }
    return result;
}

no way this is real

Recently there was a thread trying to declare PHP obsolete.

Hard to beat this in efficiency:

function is_even($num) {
    return $num % 2 === 0;
}

That said, this should work similarly in most languages.

I can't believe he needs that much code for this: bool iseven(int number){ if (number % 2 == 0){ return true; } else { return false; } }

I did something like this in high school

Modulus equals zero anyone?