this post was submitted on 21 Mar 2024
72 points (67.6% liked)

Science Memes

11597 readers
870 users here now

Welcome to c/science_memes @ Mander.xyz!

A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.



Rules

  1. Don't throw mud. Behave like an intellectual and remember the human.
  2. Keep it rooted (on topic).
  3. No spam.
  4. Infographics welcome, get schooled.

This is a science community. We use the Dawkins definition of meme.



Research Committee

Other Mander Communities

Science and Research

Biology and Life Sciences

Physical Sciences

Humanities and Social Sciences

Practical and Applied Sciences

Memes

Miscellaneous

founded 2 years ago
MODERATORS
 
all 10 comments
sorted by: hot top controversial new old
[–] OpenStars@startrek.website 58 points 10 months ago

Hrm, it sounds like the teacher already knew the answer.

Maybe stop wasting the time of the student then!?

You're welcome.

[–] Dave@lemmy.nz 53 points 10 months ago (2 children)

Can someone explain this to me? Not the maths, the joke.

[–] fossilesque@mander.xyz 42 points 10 months ago (2 children)
[–] LinkOpensChest_wav@lemmy.blahaj.zone 9 points 10 months ago (1 children)

Old man voice: "Aunt eye memes? In my day, we only had regular memes, and I turned out fine!"

[–] Venator@lemmy.nz 3 points 10 months ago

I prefer large memes

[–] driving_crooner@lemmy.eco.br 19 points 10 months ago* (last edited 10 months ago) (1 children)

The test:

Solve e^{int_0 1 x2+x+1 dx}^

[–] Usernamealreadyinuse@lemmy.world 2 points 10 months ago* (last edited 10 months ago)

No, copilot solve this test

Answer:

To solve the expression ( e^{\int_0^1 x^2+x+1 , dx} ), we first need to calculate the integral of ( x^2+x+1 ) from 0 to 1.

The integral of ( x^2+x+1 ) is: [ \int x^2+x+1 , dx = \frac{x^3}{3} + \frac{x^2}{2} + x + C ]

Evaluating this from 0 to 1 gives us: [ \left[ \frac{x^3}{3} + \frac{x^2}{2} + x \right]_0^1 = \left( \frac{1}{3} + \frac{1}{2} + 1 \right) - \left( 0 + 0 + 0 \right) = \frac{11}{6} ]

Now, we raise ( e ) to the power of this result: [ e^{\frac{11}{6}} ]

This is the solution to the given expression. If you need a numerical approximation, ( e^{\frac{11}{6}} ) is approximately 4.953.

[–] AtomfriedMegaforce@lemmy.world 4 points 10 months ago

...and this student was Albert Einstein