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How do you tackle a sudoku puzzle?
(lemmy.ml)
For each number, I mark all cells where I know I can't put it.
If one block, column or row has only one possible cell where a number can be, I put it there and then update all cells where I now know I can't put it anymore.
This algorithm probably isn't the fastest, but it's easy to do manually and it has the advantage that you don't need to backtrack.
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