this post was submitted on 20 Jan 2025
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[โ€“] TheSlad@sh.itjust.works 7 points 6 hours ago (1 children)

๐ŸŽ=376556443707

๐ŸŒ=50000000000

๐Ÿ=50000000000

[โ€“] Gladaed@feddit.org 2 points 4 hours ago (1 children)

Now do it for a case where a,b, and c are pair wise not equal.

[โ€“] TheSlad@sh.itjust.works 2 points 2 hours ago

I have to admit, my solution is not correct anyways. I simple found a "solution" for which the margin of error is smaller than the calculator's level of precision.

Sorry everyone, I cheated.

[โ€“] ChaoticNeutralCzech@feddit.org 19 points 13 hours ago (1 children)

1, 1 and 7. The sum is 3.75 โ€“ take it or leave it.

[โ€“] Tar_alcaran@sh.itjust.works 6 points 6 hours ago (1 children)

Good enough for engineers.

[โ€“] ChaoticNeutralCzech@feddit.org 7 points 6 hours ago (1 children)

Electronic engineers will know that 1, 1, 8 is closer but will go for 1, 1, 6.8 because they are in the E6 series and that will save 0.1 cents per device.

[โ€“] Tar_alcaran@sh.itjust.works 2 points 5 hours ago (1 children)

1, 1, 6.8

"6.8 isn't an integer"

"It rounds to an integer"

"The tolerance is 5% so an integer is in range"

[โ€“] De_Narm@lemmy.world 5 points 11 hours ago (1 children)

The solutions don't quite fancy me as positive whole values, see for yourself.

[โ€“] missingno@fedia.io 4 points 8 hours ago

An integer solution does exist.

[โ€“] hildegarde@lemmy.blahaj.zone 12 points 15 hours ago

no, no I can't

[โ€“] sunshine@lemmy.ml 1 points 17 hours ago (3 children)
[โ€“] ChaoticNeutralCzech@feddit.org 12 points 13 hours ago

Not the same problem.

The original solution to this one was posted by +johncbaez999 on Google Plus and reposted here.

[โ€“] Kit@lemmy.blahaj.zone 13 points 14 hours ago

Ew please don't link Reddit without warning.

[โ€“] TotallynotJessica@lemmy.blahaj.zone 11 points 15 hours ago* (last edited 15 hours ago)