this post was submitted on 16 Jun 2024
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[–] PM_Your_Nudes_Please@lemmy.world 62 points 5 months ago* (last edited 5 months ago) (1 children)

There’s a LOT of snake oil in the audio world. Especially home theater and home studio setups. I’m a professional audio technician, and some of the “audiophile” setups I have seen are just outright asinine.

Use balanced signal for runs over ~3 feet. Use the cheapest star-quad cable you can get, and the most basic $4 Neutrik connectors. Why? Because that album you’re using to test your “hi-fi” sound system was recorded using exactly that: Cheap ¢30/foot cable and basic Neutrik connectors.

It’s also what concert setups use. You think a concert with six combined miles of cabling is going to be paying $2000 per cable? Fuck no, they’re using the cheap shit (which was hand soldered in bulk at the warehouse workbench by their lowest paid shop tech), to run that million dollar audio system. Their money goes to the speakers, amps, and mixer; Not gold plated wire, robotic soldering, or triple insulated jackets. In double-blind tests, audiophiles can’t hear the difference between a $500 cable and a couple of plasti-dipped coat hangers twisted together.

The people who complain about digital audio also can’t tell the difference in double-blind tests. Because modern audio hardware is able to perfectly emulate old analog gear. Google the Nyquist–Shannon sampling theorem for a breakdown of how we can perfectly capture and recreate analog audio with digital equipment. Vacuum tubes were groundbreaking when they were first used. But they had a lot of issues, and have very little relevance in today’s systems. They’re prone to burning out, notoriously fragile, and can be emulated perfectly.

[–] intensely_human@lemm.ee 12 points 5 months ago (1 children)

The Norquist-Shannon rate sampling theorem only asserts that for a given maximum frequency, you only need another other given maximum frequency of sampling to represent it.

It does not say you can “perfectly” reproduce a signal. Only that you can reproduce all fourier components of the signal that are below half your sampling rate in frequency. It perfectly does that, yes.

But the signals that only contain a finite number of frequencies all below a certain maximum frequency are abstractions used in signal theory classes for teaching that theorem, and in engineering to hit a “good enough” target, not a “perfect” target.

Any frequencies bouncing around the room at over 22 kHz are lost at least to something using the 44 kHz sampling format.

TL;DR: Norquist-Shannon lets you completely reproduce signals with finite information in them. But real life sound doesn’t have finite information in it.

[–] Hugin@lemmy.world 5 points 5 months ago (1 children)

It's Nyquist–Shannon. Norquist is taxes.

Also frequencies greater than half the sampling rate aren't lost they fold into lower frequencies unless filtered out.

But if you think it's easiser to capture those room acoustics with analog equipment the non linear amplification and distortion of any analog system is going to change the sound just add much if not more then a good digital system.

So yeah both lose or distort the signal but digital does it in avery predictable way that can be accounted for and it does have a frequency region that it captures precisely. Analog doesn't.

[–] intensely_human@lemm.ee 5 points 5 months ago (1 children)

Nyquist, thank you.

aren't lost they fold into lower frequencies unless filtered out

If by “fold into” you mean they add noise to and hence distort the readings on the lower frequencies, that’s correct. But that just takes it further from a perfect reproduction.

[–] Hugin@lemmy.world 2 points 5 months ago (2 children)

Frequency folding is the term used in DSP no need for quotes. The Nyquist frequency is commonly referred to as the folding frequency.

And yes frequencies above the Nyquist folding frequency alias into lower frequencies. A simple low pass filter prevents this however.

Properly filtered digital sampling produced a more accurate reproduction of the frequency range with less distortion then an analog signal.

[–] intensely_human@lemm.ee 1 points 5 months ago

I don’t disagree that there’s noise in analog signals too, limiting their information capacity. But that’s coming from the limitations of our physical implementations’ quality, no?

[–] intensely_human@lemm.ee 1 points 5 months ago

Also I used quotes to refer to your words, not to throw shade at a term’s validity. I use quote marks to quote.

If by “x” you mean …

Doesn’t mean the same thing as just randomly surrounding it with quotes in normal use means.