this post was submitted on 08 Sep 2023
380 points (97.0% liked)
Asklemmy
43892 readers
865 users here now
A loosely moderated place to ask open-ended questions
Search asklemmy ๐
If your post meets the following criteria, it's welcome here!
- Open-ended question
- Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
- Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
- Not ad nauseam inducing: please make sure it is a question that would be new to most members
- An actual topic of discussion
Looking for support?
Looking for a community?
- Lemmyverse: community search
- sub.rehab: maps old subreddits to fediverse options, marks official as such
- !lemmy411@lemmy.ca: a community for finding communities
~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Also, in this simulation are the customers arriving in equally spaced intervals or is random arrival time within the bounds assumed?
In the linked article they are arriving randomly. It takes 10 minutes per customer and they arrive every 10.3 minutes.
Aren't they arriving slightly slower than can be served, according to these numbers:
If one customer takes 10 minutes to serve, you can serve 6 customers in an hour
and you get 5.8 customers every hour, which is less than 6
So you serve 6 customers, meaning you have a leftover capacity of 0.2 per hour or 1 extra customer every 5 hours
Maybe the numbers are switched over or I am misunderstanding something
Edit: nevermind, read the link in the thread and realised I treated the average as the actual serving time and I'm guessing that's what makes it non intuitive. I'm still not entirely clear on how it works.
They're arriving slower than they can be processed. So the line shrinks slowly it there's a line.