this post was submitted on 01 Sep 2023
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Programming

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[–] shagie@programming.dev 2 points 1 year ago* (last edited 1 year ago)

Talking with a rubyist:

  • 3?"bar":"qux" only has the ternary expression as a valid parsing of ?
  • foo?"bar":"qux" fails because foo may be a method and foo? is also a valid method identifier.
  • foo ?"bar":"qux" fails because ?" uses the ? unary operator that makes the next character a string. So ?"bar" becomes the string " followed by what looks to be an identifier.

And so...

  • ? character is a valid part of an identifier (but only at the end of a method name)
  • ?x unary operator to create a String from a character
  • expr?expr:expr ternary operator

And so...

puts "".empty? ? ?t:?f