this post was submitted on 01 Sep 2023
338 points (96.2% liked)
Programming
17717 readers
174 users here now
Welcome to the main community in programming.dev! Feel free to post anything relating to programming here!
Cross posting is strongly encouraged in the instance. If you feel your post or another person's post makes sense in another community cross post into it.
Hope you enjoy the instance!
Rules
Rules
- Follow the programming.dev instance rules
- Keep content related to programming in some way
- If you're posting long videos try to add in some form of tldr for those who don't want to watch videos
Wormhole
Follow the wormhole through a path of communities !webdev@programming.dev
founded 2 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Talking with a rubyist:
3?"bar":"qux"
only has the ternary expression as a valid parsing of?
foo?"bar":"qux"
fails becausefoo
may be a method andfoo?
is also a valid method identifier.foo ?"bar":"qux"
fails because?"
uses the?
unary operator that makes the next character a string. So?"bar"
becomes the string"
followed by what looks to be an identifier.And so...
?
character is a valid part of an identifier (but only at the end of a method name)?x
unary operator to create a String from a characterexpr?expr:expr
ternary operatorAnd so...