this post was submitted on 21 Dec 2024
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Fun Loops ▶️

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[–] lobut@lemmy.ca 11 points 6 days ago* (last edited 6 days ago) (1 children)

Because the abs(3) == 3 is true and that isn't even.

An even number of flips would be true and an odd number of flips would be false which works out.

I was thinking a bitwise & or converting it to a string and testing if the right most character is 0, 2, 4, 6, 8 would be panic mode solutions too.

[–] Kraiden@kbin.earth 2 points 6 days ago (1 children)

you might be able to do it with a bitwise op? My track record tonight is not great so I'm not going to comment. Have a look at @ImplyingImplactions comment for a loopless solution

[–] UID_Zero@infosec.pub 2 points 6 days ago

Bitwise and with 0x1. If result is 0, it's even. Least significant bit is always 1 for odd numbers.