this post was submitted on 05 Dec 2024

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231

if statement == false (i.imgflip.com)

submitted 3 weeks ago by tatterdemalion@programming.dev to c/science_memes@mander.xyz

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[–] juliebean@lemm.ee 62 points 3 weeks ago (5 children)

what would be the alternative? to always execute if the condition is true, but sometimes execute it even when false, for funsies?

[–] ptz@dubvee.org 41 points 3 weeks ago* (last edited 3 weeks ago) (3 children)

Hey, I like a little chaos in my codebase 😆

const funsies = () => (Math.round(Math.random() * 1000) % 2 == 0)
if ( condition || funsies() ) {
    // do the thing
}

[–] sorrybookbroke@sh.itjust.works 6 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

Wait, why the the *1000 or mod 2? Won't that give a 50\50 chance or the same as Math.round(Math.random).

No shade, and I may be wrong myself I am very tired

[–] mexicancartel@lemmy.dbzer0.com 2 points 3 weeks ago

Probably to make the fractional random value between 0 and 1 to become an integer so that you can divisibility check for even with mod 2

[–] modality@lemmy.myserv.one 4 points 3 weeks ago (1 children)

is this AI?

[–] ptz@dubvee.org 19 points 3 weeks ago* (last edited 3 weeks ago)

Nope. I'm staunchly against "AI". If the code sucks, it's because I wrote bad code.

Edit: Oh, or did you mean is that how "AI" works?

[+] sorrybookbroke@sh.itjust.works 1 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

[deleted]

[–] ptz@dubvee.org 3 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

In Javascript, Math.random() produces a float value between 0 and 1, so I multiply by 1000 and round it to get a larger integer. The value %2 == 0 is a non-library way of performing isEven() on the random integer (value % 2 is 0 if even, 1 if odd, and the ==0 makes it return a boolean). When used in the if statement, it's essentially a coin flip.

[–] juliebean@lemm.ee 3 points 2 weeks ago (1 children)

does javascript not allow you to interpret integers as booleans in a conditions directly? seems it'd be simpler to just do math.round(math.random()), which should still get you true (1) or false (0) in equal likelihood. or am i missing something?

[–] ptz@dubvee.org 1 points 2 weeks ago* (last edited 2 weeks ago) (1 children)

It'll give you 1 ~= true or 0 ~= undefined, but I typically use Typescript which prefers actual booleans to boolean-ish

[–] juliebean@lemm.ee 1 points 2 weeks ago

huh. interesting. i wonder what number it's actually storing for false then?

[–] bstix@feddit.dk 19 points 3 weeks ago (1 children)

The "only" part implies exclusivity, which may be false, because other things might run the code anyway.

IF "I can see the sun" THEN "It's day."

Nothing wrong about that. However if we make it exclusive:

IF AND ONLY IF "I can see the sun" THEN "It's day."

That's obviously wrong. I can actually not keep the day away by sitting with closed eyes in my mothers basement with the curtains shut.

"Only if" might make sense in a legal contract, but there's no way a piece of code can stop other pieces of code from calling the same functions.

[–] adj16@lemmy.world 2 points 3 weeks ago (1 children)

But that’s not how if statements in code work. So what you’ve said isn’t wrong, but the premise of this meme is completely off

[–] bstix@feddit.dk 2 points 2 weeks ago* (last edited 2 weeks ago)

Yes sure. Code is logical stepwise. By including the "only if" it implies that other stuff is taken into account, which it isn't at that moment in code.

I mean, I don't need to extend the implications of an IF statement. It already does exactly what it says.

Anyway fuzzy logic does exist for people who want "sometimes if". It's useful in certain cases. I've only ever considered it in music production, where things very often get to the point of complexity where it makes a (sometimes) useful difference.

[–] General_Effort@lemmy.world 7 points 3 weeks ago* (last edited 3 weeks ago)

In normal parlance, "if and only if" rules out that something could also happen as a result of other circumstances. EG, if you fall out of a plane, you will lose your glasses. But there are other conditions that would lead to the same result.

In code, the alternative would be to have a different if statement that executes identical code. Or *cough* you could use a jump instruction to execute literally the same code.

[–] unmagical@lemmy.ml 1 points 3 weeks ago

Brb, making a truly "if" statement function in my products code base for funsies.