this post was submitted on 25 Jun 2023
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Welp.

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[–] FinnTheFickle@kbin.social 59 points 1 year ago (11 children)

What the fuck did Logitech do wrong here? If anything, that controller was the most functional part of the sub

[–] phantomslave@kbin.social 10 points 1 year ago (1 children)

Put it in a bag of rice and it probably still works! Assuming it's still whole.

[–] Pseu@kbin.social 8 points 1 year ago (1 children)

It's not. When the sub collapsed, it did so with the energy of about 50kg of TNT.

This is why there will be no attempt to recover the bodies either. There just isn't anything left.

[–] Decidable@kbin.social 5 points 1 year ago (3 children)

Fascinating. Where did you get those numbers, I'd like to read more.

[–] WhiskyTangoFoxtrot@lemmy.world 14 points 1 year ago (1 children)

There's a row of them along the top of the keyboard, and another block of them on the right-hand side.

[–] RheingoldRiver@kbin.social 2 points 1 year ago (1 children)

help, I tried pressing the ones on the right, but my cursor just started moving all over the place. Did you hack my keyboard?

[–] WhiskyTangoFoxtrot@lemmy.world 1 points 1 year ago (1 children)
[–] RheingoldRiver@kbin.social 2 points 1 year ago (1 children)

Ok, I've sent [up][left][left][left][down][down][down][down][right] bitcoin to the address [up][up][down][down][left][right][left][right]...[enter]. I hope you're happy now.

I think I've got 30 lives.

[–] TheYang@kbin.social 4 points 1 year ago

W = p Δ V
The Sub had a Volume of the 142 cm (56 in) internal diameter, 2.4-meter-long (7.9 ft) carbon fiber-wound cylinder
so 3.8m³ of air, should be about 3.8m³ x 4x10⁷ Pa = 152x10⁶ J, 152MJ

TNT has about 4.2x10⁶J/kg, so I get about 36kg of TNT.
But I ignored the front and back Domes, which will add a bit, and possibly have other issues as well, so the ballpark should be right.

[–] Pseu@kbin.social 1 points 1 year ago

I got them from this Scott Manley video: https://www.youtube.com/watch?v=qdz9vcSFBqw

He explains that the energy contained in a vessel is equal to the difference in pressure on the vessel wall, times the volume of the container.

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