this post was submitted on 01 Dec 2024
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Having two possible outcomes does not mean it's a 50:50 chance.
"So if I aim the arrow at the 1cm square from 100m away and shoot, I either hit it or I don't. So basically I have a 50% chance of hitting it."
Very weird fun fact about arrows/darts and statistics, theres 0% chance of hitting an exact bullseye. You can hit it its possible to throw a perfect bullseye. It just has a probability of zero when mathematically analyzed due to being an infinitesimally small point. Sound like I'm making shit up? Here's the sauce
How can an outcome both be entirely possible and have 0% probability?
Q.E.D
Key word here is "infinitesimally." Of course if you're calculating the odds of hitting something infinitesimally small you're going to get 0. That's just the nature of infinities. It is impossible to hit an infinitesimally small point, but that's not what a human considers to be a "perfect bullseye." There's no paradox here.
Another lesson I the importance of significant digits, a concept I've had to remind many a young (and sometimes an old) engineer about. An interesting idea along similar lines is that 2 + 2 can equal 5 for significantly large values of 2.
What do you mean by significantly large
Depending on how you're rounding, I assume. Standard rounding to whole digits states that 2.4 will round to 2 but 4.8 will round to 5. So 2.4+2.4=4.8 can be reasonably simplified to 2+2=5.
This is part of why it's important to know what your significant digits are, because in this case the tenths digit is a bit load bearing. But, as an example, 2.43 the 3 in the hundredths digit has no bearing on our result and can be rounded or truncated.